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How to display money values in currency format?

Execute the following Microsoft SQL Server T-SQL example scripts in Management Studio Query Editor to demonstrate the formatting of money values/columns into currency (USD - U.S. Dollar - $) with thousands separators and English text (currency in words) formats.

-- Leading asterisks fill USD currency with thousands separators - QUICK SYNTAX

SELECT '$'+STUFF(convert(varchar,convert(money,12345),1), 1, 0,

           REPLICATE('*', 12 - LEN(convert(varchar,convert(money,12345),1))))

-- $***12,345.00

-- SQL format money with commas - thousand separators - transact sql format currency

-- SQL Server currency formatting and rounding - sql server convert formats

DECLARE @Amount MONEY = 28699654.7766      -- SQL Server 2008 t-sql syntax

SELECT DollarAmount=CONVERT(VARCHAR,@Amount,1)    -- 28,699,654.78

SELECT DollarAmount=CONVERT(VARCHAR,@Amount)      -- 28699654.78

SELECT DollarAmount=CONVERT(VARCHAR,@Amount, 0)   -- 28699654.78


-- String to money conversion

DECLARE @money1 varchar(64) = '-222,111,333.88',

        @money2 varchar(64) = '$123,456.93'

SELECT Money1 = CONVERT(money, @money1), Money2 = CONVERT(money, @money2)

-- -222111333.88  123456.93

------------

-- $ Prefix money / currency, & insert commas / pad with zeros - sql money formats

SELECT DollarAmount='$'+CONVERT(VARCHAR,@Amount,1)       -- $28,699,654.78

SELECT [USD Amount]=CHAR(36)+CONVERT(VARCHAR,@Amount,1)  -- $28,699,654.78

SELECT '$'+RIGHT('0000000000000000'+CONVERT(VARCHAR,@Amount),16) -- $0000028699654.78

-- SQL format currency in SELECT statement - sql format money - sql format currency

SELECT TOP (2) SalesOrderID, Total='$'+CONVERT(VARCHAR, TotalDue,1)

FROM AdventureWorks2008.Sales.SalesOrderHeader

/*          SalesOrderID      Total

            43659             $27,231.55

            43660             $1,716.18  */


-- Displaying calculated money values in currency format in t sql - sql currency formats

SELECT TOP (3) SalesOrderDetailID, '$'+

CONVERT(varchar, OrderQty * (1-UnitPriceDiscount)* UnitPrice,1) AS DetailTotal

FROM AdventureWorks2008.Sales.SalesOrderDetail ORDER BY NEWID()

/*    SalesOrderDetailID      DetailTotal

      40284                   $4,033.76

      34991                   $3,239.97

      10055                   $5.19    */

-- SQL currency formatting aligned right - sql server format currency
SELECT
   TOP (3)  ProductName=Name,

                  Price=  '$' + CONVERT(char(8), ListPrice, 1)

FROM Production.Product

WHERE ListPrice > 0.0 ORDER BY Newid()

/* ProductName                            Price

Road-250 Black, 52                        $2,443.35

LL Mountain Seat/Saddle                   $   27.12

LL Touring Frame - Blue, 50               $  333.42  */

-- SQL currency without decimals - currency decimal places - convert currency sql

DECLARE @MoneyValue money = 2391590

SELECT CurrencyNoDecimals = '$'+ LEFT( CONVERT(varchar, @MoneyValue,1),

   LEN (CONVERT(varchar, @MoneyValue,1)) - 3)

-- $2,391,590

-- SQL convert string currency format to money - convert string to money sql

SELECT CONVERT(MONEY,'$123,456.34')

SELECT CONVERT(MONEY,'123,456.34')

-- 123456.34

-- USD currency format without cents

SELECT PARSENAME('$'+ Convert(varchar,Convert(money,5550000.45),1),2)

-- $5,550,000

------------

------------

-- Forcing floating point rate calculation with MONEY data types

------------

SELECT ProductName = Name,

       CostRate = 1.0 * StandardCost / ListPrice

FROM AdventureWorks2008.Production.Product

WHERE ListPrice > 0

ORDER BY CostRate

/*    ProductName                   CostRate

      Mountain Bike Socks, M        0.35750526315789473

      Mountain Bike Socks, L        0.35750526315789473

      Fender Set - Mountain         0.37399909008189262

      All-Purpose Bike Stand        0.37400000000000000 ..../

------------

Article: Performance / Storage Comparisons : MONEY vs. DECIMAL

/* The column type has to be monetary data type (money or smallmoney)

for currency formatting. If not, it has to be converted to money type first.

Money data type can store values in the range from -922,337,203,685,477.5808

through +922,337,203,685,477.5807 (8 bytes); Smallmoney data type range is

from -214,748.3648 through 214,748.3647 (4 bytes). */

-- T-SQL currency formatting function - scalar-valued, user-defined

CREATE FUNCTION fnFormatCurrency

               (@MoneyAmount MONEY)

RETURNS VARCHAR(24)

AS

  BEGIN

    RETURN ('$' + convert(VARCHAR,@MoneyAmount,1))

  END

GO

 

-- Test / call currency formatting function with money type monetary input

SELECT TOP ( 3 ) SalesYTD,

                 CurrencyFormat = dbo.fnFormatCurrency(SalesYTD)

FROM     Sales.SalesPerson

ORDER BY NEWID()

GO

/*    SalesYTD          CurrencyFormat

      1764938.9859      $1,764,938.99

      3018725.4858      $3,018,725.49

      3189356.2465      $3,189,356.25

*/

------------

-- T-SQL double convert: convert decimal to money --> convert to varchar currency format

-- SQL Server 2008 T-SQL syntax - display money values in currency format

DECLARE @AccountBalance decimal(12,2) = 453789345.34

SELECT CONVERT(varchar(16),CONVERT(money, FLOOR(2 * @AccountBalance)),1)

-- 907,578,690.00

 

-- T-SQL basic currency formatting - format money/decimal

use AdventureWorks2008

declare @Amount money = 987654321.2355

select      Currency=convert(varchar, @Amount, 1), 

            TwoDecimals=cast(@Amount as decimal(12,2))

/*

Currency          TwoDecimals

987,654,321.24    987654321.24

*/

 

-- SQL money formatting

-- SQL format 2 money type columns to currency - convert datetime to date

SELECT   TOP 5 SalesOrderID,

               [Order Date] = CONVERT(DATE,OrderDate),

               SubTotal = '$' + CONVERT(VARCHAR,SubTotal,1),

               [Total Due] = '$' + CONVERT(VARCHAR,TotalDue,1)

FROM     AdventureWorks2008.Sales.SalesOrderHeader

ORDER BY NEWID()

/*

SalesOrderID      Order Date  SubTotal    Total Due

44427             2001-10-20  $3,578.27   $3,953.99

67093             2004-03-29  $27.77      $30.69

72730             2004-06-12  $2,419.06   $2,673.06

54657             2003-09-20  $2,443.35   $2,699.90

45318             2002-02-01  $36,073.76  $39,861.50

*/

-- SQL varchar currency formatting options with parameter 0, 1, 2

SELECT CONVERT(varchar, CONVERT(money, 453757395.549535), 0 ) -- 453757395.55

SELECT CONVERT(varchar, CONVERT(money, 453757395.549535), 1 ) -- 453,757,395.55

SELECT CONVERT(varchar, CONVERT(money, 453757395.549535), 2 ) -- 453757395.5495
------------

-- T-SQL money data type has 4 digits after the decimal point

-- Microsoft T-SQL money & smallmoney data types are accurate to a ten-thousandth 

-- MSSQL text / string numeric literal value rounded to money format

-- SQL cast money - cast currency

SELECT CAST(999.123456789 AS money)

-- 999.1235
------------

USE AdventureWorks;

-- SQL currency format - sql convert money to string - right justify string

-- SQL format currency - format numeric output - sql string formatting

-- SQL money format - transact sql money conversion

-- MSSQL format money - right align output - right adjust string

SELECT   TOP ( 7 )

    SubTotal,

    CurrencyFormat = Convert(VARCHAR(12),SubTotal,1),

    MoneyFormat = '$' + Convert(VARCHAR(12),SubTotal,1),

    RightJustified=

      REPLICATE(' ', 15 - len ('$' + Convert(VARCHAR(12),SubTotal,1) )) +

                '$' + Convert(VARCHAR(12),SubTotal,1)

FROM     Sales.SalesOrderHeader

ORDER BY Newid()

GO

/*

SubTotal    CurrencyFormat    MoneyFormat   RightJustified

2369.96     2,369.96          $2,369.96         $2,369.96

4450.7456   4,450.75          $4,450.75         $4,450.75

17476.3368  17,476.34         $17,476.34       $17,476.34

69.99       69.99             $69.99               $69.99

1288.31     1,288.31          $1,288.31         $1,288.31

2448.04     2,448.04          $2,448.04         $2,448.04

42.97       42.97             $42.97               $42.97

*/

------------

-- SQL check printing - format dollar amount with left asterisk padding

-- SQL currency formatting - transact sql format currency

-- MSSQL money formatting

DECLARE  @Amount MONEY

SET @Amount = '2534.40'

SELECT DollarFormat =  '$' +

                        Replicate('*',12 - Len(Convert(VARCHAR,@Amount,1))) +

                        Convert(VARCHAR,@Amount,1)

-- SQL equivalent currency formatting with asterisk-fill
SELECT
DollarFormat = '$' + REPLACE(Convert(char(12),@Amount,1),' ','*')
GO

-- Result: $****2,534.40

 

------------

-- SQL convert currency in string format back to money or decimal

-- SQL convert currency formatted string to numeric

DECLARE @Currency varchar(64)

SET @Currency = '$5,399.23'

SELECT StringCurrency = @Currency,

MoneyFormat=CAST (REPLACE(REPLACE(@Currency, '$',''),',','') AS MONEY)

GO

/* Results

 

StringCurrency    MoneyFormat

$5,399.23         5399.23

*/

------------

-- SQL format money dollars only - format money without cents

-- SQL format money no cents - format amount whole number only

-- MSSQL format currency without decimals

SELECT TOP (5) ProductName = Name,

      ListPrice = LEFT('$' + CONVERT(VARCHAR, CAST(ListPrice AS MONEY), 1),

                   LEN('$' + CONVERT(VARCHAR, CAST(ListPrice AS MONEY), 1)) - 3)

FROM AdventureWorks.Production.Product

WHERE ListPrice > 0.0

ORDER BY newid()

/*

ProductName                         ListPrice

ML Road Rear Wheel                  $275

HL Road Seat/Saddle                 $52

Road-250 Black, 48                  $2,443

HL Mountain Frame - Black, 44       $1,349

LL Road Frame - Black, 60           $337

*/
------------
   

------------

-- Decimal to Currency converter

------------

-- SQL convert decimal to currency UDF - insert commas / thousand separators

-- T-SQL string scalar-valued user-defined function - convert varchar to money

CREATE FUNCTION fnDecimalToCurrency

              (@Amount DECIMAL(38,2))

RETURNS VARCHAR(64)

AS

  BEGIN

    DECLARE  @Result VARCHAR(64),

             @Buffer VARCHAR(64),

             @Comma  CHAR(1)

    SET @Result = ''

    SET @Comma = ''

    SET @Buffer = convert(VARCHAR(64),@Amount)

    SET @Result = right(@Buffer,3)

    SET @Buffer = left(@Buffer,len(@Buffer) - 3)

    WHILE (len(@Buffer) > 0)

      BEGIN

        SET @Result = left(convert(VARCHAR,convert(MONEY,reverse(

                                  left(reverse(@Buffer),12))),

                                   1),len(convert(VARCHAR,convert(MONEY,

                                   reverse(left(reverse(@Buffer),12))),

                                            1)) - 3) + @Comma + @Result

        SET @Buffer = CASE

                        WHEN len(@Buffer) > 12

                          THEN left(@Buffer,len(@Buffer) - 12)

                        ELSE ''

                      END

        SET @Comma = ','

      END

    RETURN REPLACE(@Result,' ','')

  END

GO

 

-- Test / call user-defined function

SELECT dbo.fnDecimalToCurrency(123456789012345678901234567890.12)

-- 123,456,789,012,345,678,901,234,567,890.12

SELECT dbo.fnDecimalToCurrency(5123.1244)     -- 5,123.12

SELECT dbo.fnDecimalToCurrency(67364676.126)  -- 67,364,676.13

The BEST 70-461 SQL Server 2012 Querying Exam Prep Book!

------------

-- SQL convert dollar amount into words for check printing - Dollars and cents format

------------

-- Convert numbers to words - SQL amount into words - Currency to words

-- SQL money format to English - Translate money to text

-- Translate dollar amount to words - Convert numbers into English words

/*******

* Special thanks to Hunchback and Gert-Jan Strik of MSDN T-SQL forum for the nest level solution

*******/

USE AdventureWorks2008;

GO

-- Convert numbers to text - Scalar-valued user-defined function - UDF

CREATE FUNCTION fnMoneyToEnglishNL(@Money AS money, @nl int)

    RETURNS VARCHAR(1024)

AS

BEGIN

      DECLARE @Number as BIGINT

      SET @Number = FLOOR(@Money)

      DECLARE @Below20 TABLE (ID int identity(0,1), Word varchar(32))

      DECLARE @Below100 TABLE (ID int identity(2,1), Word varchar(32))

 

      INSERT @Below20 (Word) VALUES

                        ( 'Zero'), ('One'),( 'Two' ), ( 'Three'),

                        ( 'Four' ), ( 'Five' ), ( 'Six' ), ( 'Seven' ),

                        ( 'Eight'), ( 'Nine'), ( 'Ten'), ( 'Eleven' ),

                        ( 'Twelve' ), ( 'Thirteen' ), ( 'Fourteen'),

                        ( 'Fifteen' ), ('Sixteen' ), ( 'Seventeen'),

                        ('Eighteen' ), ( 'Nineteen' )

       INSERT @Below100 VALUES ('Twenty'), ('Thirty'),('Forty'), ('Fifty'),

                               ('Sixty'), ('Seventy'), ('Eighty'), ('Ninety')

 

DECLARE @English varchar(1024) =

(

  SELECT Case

    WHEN @Number = 0 THEN  ''

    WHEN @Number BETWEEN 1 AND 19

      THEN (SELECT Word FROM @Below20 WHERE ID=@Number)

   WHEN @Number BETWEEN 20 AND 99

-- SQL Server recursive function   

     THEN  (SELECT Word FROM @Below100 WHERE ID=@Number/10)+ '-' +

           dbo.fnMoneyToEnglishNL( @Number % 10, @nl)

   WHEN @Number BETWEEN 100 AND 999  

     THEN  (dbo.fnMoneyToEnglishNL( @Number / 100, @nl))+' Hundred '+

         dbo.fnMoneyToEnglishNL( @Number % 100, @nl)

   WHEN @Number BETWEEN 1000 AND 999999  

     THEN  (dbo.fnMoneyToEnglishNL( @Number / 1000, @nl))+' Thousand '+

         dbo.fnMoneyToEnglishNL( @Number % 1000, @nl) 

   WHEN @Number BETWEEN 1000000 AND 999999999  

     THEN  (dbo.fnMoneyToEnglishNL( @Number / 1000000, @nl))+' Million '+

         dbo.fnMoneyToEnglishNL( @Number % 1000000, @nl)

   ELSE ' INVALID INPUT' END

)

SELECT @English = RTRIM(@English)

SELECT @English = RTRIM(LEFT(@English,len(@English)-1))

                 WHERE RIGHT(@English,1)='-'

IF (@@NestLevel - @nl) = 1

BEGIN

      SELECT @English = @English+' Dollars and '

      SELECT @English = @English+

      convert(varchar,convert(int,100*(@Money - @Number))) +' Cents'

END

RETURN (@English)

END

GO

------------

CREATE FUNCTION fnMoneyToEnglish(@Money AS money)

    RETURNS VARCHAR(1024)

AS

BEGIN

  RETURN (dbo.fnMoneyToEnglishNL(@Money, @@NESTLEVEL))

END

------------

-- Test number to English dollar and cents translation function

-- SQL convert number to text

SELECT NumberInEnglish=dbo.fnMoneyToEnglish ( 67)

-- Sixty-Seven Dollars and 0 Cents

SELECT NumberInEnglish=dbo.fnMoneyToEnglish ( 947.54)

-- Nine Hundred Forty-Seven Dollars and 54 Cents

SELECT NumberInEnglish=dbo.fnMoneyToEnglish ( 1266.04)

-- One Thousand Two Hundred Sixty-Six Dollars and 4 Cents

SELECT NumberInEnglish=dbo.fnMoneyToEnglish ( 4261.25)

-- Four Thousand Two Hundred Sixty-One Dollars and 25 Cents

SELECT NumberInEnglish=dbo.fnMoneyToEnglish ( 921456321.88)

/* Nine Hundred Twenty-One Million Four Hundred Fifty-Six Thousand

Three Hundred Twenty-One Dollars and 88 Cents */

GO

------------

-- SQL crosstab query with pivot and currency formatting

USE AdventureWorks;

-- SQL format money - money values in currency format

-- SQL money format - format purchase amount

-- SQL currency format - dollar format

WITH ctePurchaseSummary(OrderYear,PurchasingAgent,SubTotal)

     AS (SELECT Year(OrderDate),

                FirstName + ' ' + LastName,

                SubTotal

         FROM   Purchasing.PurchaseOrderHeader pod

                JOIN HumanResources.Employee e

                  ON pod.EmployeeID = e.EmployeeID

                JOIN Person.Contact c

                  ON e.ContactID = c.ContactID

         WHERE  pod.EmployeeID IS NOT NULL)

-- !! USE commented out query below to establish PIVOT list

-- SELECT DISTINCT OrderYear FROM ctePurchaseSummary

SELECT PurchasingAgent,

       '$' + Convert(VARCHAR,Isnull(pvt.[2001],0),1) AS [2001],

       '$' + Convert(VARCHAR,Isnull(pvt.[2002],0),1) AS [2002],

       '$' + Convert(VARCHAR,Isnull(pvt.[2003],0),1) AS [2003],

       '$' + Convert(VARCHAR,Isnull(pvt.[2004],0),1) AS [2004]

FROM   ctePurchaseSummary

       PIVOT

       (Sum(SubTotal)

        FOR OrderYear IN ( [2001],[2002],[2003],[2004] ) ) AS pvt

GO

/* Partial results

 

PurchasingAgent         2001        2002              2003                    2004

Annette Hill            $0.00       $413,492.82       $1,524,567.78     $3,300,836.09

Arvind Rao              $0.00       $213,779.08       $644,905.37       $1,836,735.27

Ben Miller              $0.00       $419,330.79       $1,314,197.33     $2,959,713.61

Eric Kurjan             $8,847.30   $274,629.19       $1,422,375.48     $4,577,239.22

Erin Hagens             $201.04     $227,578.27       $1,417,972.59     $3,384,343.91

Frank Pellow            $693.38     $389,803.98       $1,513,463.28     $4,026,137.08

*/

------------

------------

-- SQL right align numeric data

------------

-- SQL align numeric output - format money with thousand separators

-- SQL format money - align column right - format money with commas - right adjust

DECLARE @Width tinyint = 20;

SELECT   TOP ( 5 ) ProductName = Name,

                   [Price Aligned Right] =

    REPLICATE(' ',@Width - 1 - LEN(CONVERT(VARCHAR,ListPrice,1))) +

             '$' + CONVERT(VARCHAR,ListPrice,1)

FROM     AdventureWorks2008.Production.Product

WHERE    ListPrice > 0.0

ORDER BY NEWID()

GO

/* Results

 

ProductName                         Price Aligned Right

LL Fork                                         $148.22

Chain                                            $20.24

HL Touring Seat/Saddle                           $52.64

Road-450 Red, 44                              $1,457.99

LL Touring Frame - Yellow, 44                   $333.42

*/

------------

Related articles:

Displaying money values in currency format in SQL

Create SQL Function To Format To Currency - display money and currency amounts in the currency format using User-Defined Function in SQL Server

 

Exam Prep 70-461
Exam 70-461